To draw the graph of 2x + 3y = 12, find x, when y = 6 and find y, when x = 3. Write in ordered pair.
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2x+3y=12⋯(1)
To draw the graph ,we need at least two solutions of the equation
Put x=0 in (1)
2(0)+3y=12
⟹3y=12
⟹y=4
So (0,4) is a solution of the equation
Put y=0 in (1)
2x+3(0)=12
⟹2x=12
⟹x=6
So (6,0) is a solution of the equation
With these two equations we can draw graph of 2x+3y=12
from the graph
(i) when y=3 then x=1.5
So, point is (1.5,3)
(ii) when x=−3 then y=6
So, point is (−3,6)
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Given :-
2x + 3y = 12
To Find :-
Graph, x and y
Solution :-
When y = 6
2x + 3y = 12
2x + 3(6) = 12
2x + 18 = 12
2x = 12 - 18
2x = -6
x = -6/2
x = -3
Co-ordinate = (-3,0)
When x = 3
2(3) + 3y = 12
6 + 3y = 12
3y = 12 - 6
3y = 6
y = 6/3
y = 2
Intersection point = (0,4)
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