to draw velocity time graph for uniform motion and calculate acceleration and displacement
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Answered by
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Formula used:
velocity = Displacementtime
∴Displacement = Velocity×time
Complete step-by-step answer:
In uniform motion, the speed of the body remains constant, that is, the magnitude of the velocity does not change as there is no tangential acceleration.
Since, acceleration is the slope of the velocity-time graph, if it is zero, then the slope will also be zero. Therefore, the graph will be nothing but a straight horizontal line with zero slope.
Therefore, let us now draw the graph.
To show that the area under the velocity time graph gives the displacement of the body, we will find out the area of the rectangle between the dotted lines as shown in the graph.
Since, the area of the rectangle is nothing but its length×breadth
, we will get the area of the rectangle as v×(t2−t1)
v
×
(
t
2
−
t
1
)
--(1)
Where v
v
is the constant magnitude of velocity of the body and (t2−t1)
(
t
2
−
t
1
)
is the span of the time interval.
Now, velocity = Displacementtime
velocity =
Displacement
time
∴Displacement = Velocity×time
∴
Displacement = Velocity
×
time
--(2)
Hence, comparing (1) and (2), we get,
The area under the rectangle is nothing but the displacement covered by the body in that time interval.
velocity = Displacementtime
∴Displacement = Velocity×time
Complete step-by-step answer:
In uniform motion, the speed of the body remains constant, that is, the magnitude of the velocity does not change as there is no tangential acceleration.
Since, acceleration is the slope of the velocity-time graph, if it is zero, then the slope will also be zero. Therefore, the graph will be nothing but a straight horizontal line with zero slope.
Therefore, let us now draw the graph.
To show that the area under the velocity time graph gives the displacement of the body, we will find out the area of the rectangle between the dotted lines as shown in the graph.
Since, the area of the rectangle is nothing but its length×breadth
, we will get the area of the rectangle as v×(t2−t1)
v
×
(
t
2
−
t
1
)
--(1)
Where v
v
is the constant magnitude of velocity of the body and (t2−t1)
(
t
2
−
t
1
)
is the span of the time interval.
Now, velocity = Displacementtime
velocity =
Displacement
time
∴Displacement = Velocity×time
∴
Displacement = Velocity
×
time
--(2)
Hence, comparing (1) and (2), we get,
The area under the rectangle is nothing but the displacement covered by the body in that time interval.
Answered by
2
Answer:
this is ur correct answrr
hope it help u
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