To electric bulbs P and Q have their resistances in the ratio of 1:2. They are connected in series across a battery. Find the ratio of the power dissipation in these bulbs.
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Power dissipation (P)=I^2R
Pa = power dissipation of bulb P
Pb = power dissipation of bulb Q
Pa/Pb = I^2Ra/I^2Rb
as current is same across the circuit so
Pa/Pb = Ra/Rb which is given 1:2
Pa/Pb = 1:2
Pa = power dissipation of bulb P
Pb = power dissipation of bulb Q
Pa/Pb = I^2Ra/I^2Rb
as current is same across the circuit so
Pa/Pb = Ra/Rb which is given 1:2
Pa/Pb = 1:2
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