To fence a rectangular farm of 750 m², 110 m of fence has been used. Calculate the dimensions of the farm.
Answers
perimeter 2(l+b)=110
we know that
(l+b)^2=(l-b)^2+4lb
55^2=(l-b)^2+4*750
3025=(l-b)^2+3000
(l-b)^2=3025-3000
(l-b)^2=25
(l-b)=5
so,
solve equations
l+b=55 and l-b=5
l=30
substitute in any of the above equations u will get
b=25
therefore the dimensions of the farm are 30m and 25m
The dimensions of the farm are 30m & 25m
Step-by-step explanation:
Given:
Area of the rectangular farm = 750m²
Fence used for the farm= 110m
To find:
the dimensions of the farm
Solution:
The area of the farm is 750sqm
Now, as we know,
Area of farm = L X B
∴ 750 = L X B.................(1)
The fence required is given
That is the perimeter of the farm is 110m
∴ The perimeter of the farm = 2(L+B)
∴ 110 = 2(L+B)
∴ 110/2 = (L+B)
∴ 55 = (L+B)
∴ 55 - L = B
∴ B = 55-L ........................(2)
Putting (2) in equation (1)
∴ 750 = L X B
∴ 750 = L X (55-L)
∴ 750 = 55L-L²
∴ 55L- L²= 750
∴ L²-55L + 750 = 0
Solving using quadratic equations
∴ L²-30L-25L+ 750 = 0
∴ L(L-30)- 25(L-30) = 0
∴ (L-30) (L-25) =0
∴ (L-30)= 0 or (L-25) =0
∴ L= 30 or L= 25
When L = 30m the breadth (B) will be B = 55-30 = 25m
and when L= 25m the breadth (B) will be B = 55-25 =30m
Thus, the dimensions of the farm are 30m & 25m
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