Question

To fill 12 vacancies there are 25 candidates of which 5 are from scheduled castes. If 3 of the vacancies are reserved for scheduled caste candidates while the rest are open to all, the number of ways in which the selection can be made is 5C3 x 22C9.​

Answer 1

Answer:

Since, order of selection is not required and hence we will be using Combination Formula

Now, there are 3 vacancies reserved for 5 SCs, So we will first allot vacancies to them whose number of ways are

=

5

C

3

Now, after allotting 3 vacancies to SCs , now 9 vacancies will remain of the 12 and 22 candidates will remain out of 25 in which 2 SCs are also included as the rest vacancies are open to all , hence the number of ways

=

22

C

9

Total number of selections =

5

C

3

∗

22

C

9

=

Answer 2

Answer:

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