Math, asked by sripadmapriya76, 22 days ago

to find: cos(A+B) cosC-cos(B+C) cosA=sinBsin(C-A)

Answers

Answered by divyanshikhandwal

Answer:

= (cosAcosB - sinAsinB)cosC - (cosBcosC - sinBsinC)cosA= cosAcosBcosC - sinAsinBcisC - cosAcosBcosC + sinBsinCcosA= sinBsinCcosA - sinBsinAcosC= sinB(sinCcosA - cosCsinA)= sinBsin (C- A)

Step-by-step explanation:

$itzdivyanshi$

Previous Question

Next Question

Similar questions

Geography, 11 days ago

Is newspaper is a audio -visual ...

English, 11 days ago

the girnar is the highest mountain peak of gujarat change the degree...

Biology, 11 days ago

is mainly used in Gujarat...

Hindi, 22 days ago

किताबें ' कविता में आया एक प्रसिद्ध पेड़ का नाम :- *...

Hindi, 22 days ago

भभूत लगाने से लेखक क्या बन जाते थे...

Math, 8 months ago

By what number should ${( - 30)}^{ - 1}$ be divided to get ${6}^{ - 1}$ ???

Hindi, 8 months ago

Do mikto ke bhich savah in hindi...

Biology, 8 months ago

What is dibetes mellitus? Mention its symptoms...

to find: cos(A+B) cosC-cos(B+C) cosA=sinBsin(C-A) ​

Answers

to find: cos(A+B) cosC-cos(B+C) cosA=sinBsin(C-A)