Question

to find dy/dx, y=cosx co2x co3x​

Answer 1

Answer:

-sinx.2cos2x.3 cos3x..............

Answer 2

Step-by-step explanation:

$\frac{dy}{dx} = \frac{d(cosx \times cos2x \times cos3x)}{dx}$

dy/dx =

-sinx.cos2x.cos3x-2.cosx.sin2x.cos3x-3cosx.cos2x.sin3x

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