to find the centre of a circle whose centre is not known
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Answered by
0
Answer:
Given the centre is at (α,β)
The equation of circle be,
(x−α)
2
+(y−β)
2
=r
2
The circle passes through origin
∴α
2
+β
2
=r
2
Hence the equation of circle becomes
x
2
+y
2
−2αx−2βy=0
The equation of tangent at point (x
1
,y
1
) for a standard equation of circle x
2
+y
2
+2gx+2fy+c=0 is
xx
1
+yy
1
+g(x+x
1
)+f(y+y
1
)+c=0
gx+fy+c=0
g=−α,f=−β,c=0
∴αx+βy=0.
Answered by
1
Answer:
hi
Step-by-step explanation:
use a compass
expand it by its radious
then draw
u will get
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