Question

to find the current acroos the branch by kvl or kcl

Answer 1

Mesh 1:-2I1+2(I1+I2)=6v

⟹4I1−2I2=6v

⟹2I1−I2=3→(1)

Mesh 2:-4I2+2(I1+I2)=2v

⟹6I2−2I1=2→(2)

Equating (2) and (1)

I2=1A

I1=2A

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