to find the HCF of two five integers and find HCF of 475 and 495
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Answered by
1
HCF of 475 and 495 is :
•495=475*1+20.
•475=20*23+15.
•20=15*1+5.
•15=5*3+0.
•Hence HCF of 475 and 495 is 5.
Hope it helps u...
Answered by
3
495 = 475 x 1 + 20.
Since remainder ≠ 0, apply division lemma on 475 and remainder 20
475 = 20 x 23 + 15.
Since remainder ≠ 0, apply division lemma on 20 and remainder 15
20 = 15 x 1 + 5.
Since remainder ≠ 0, apply division lemma on 15 and remainder 5
15 = 5 x 3+ 0.
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