to find the hcf of two number experimentally based on euclid divison lemma
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a=bq+r where,
a= divident
b_ divisor
q_ quotient
r._remainder
example 237 and 81
237=81×2+75
81=75×1+6
75=6×12+3
6=3×2+0
hcf =3
:- till we get remainder has 0 till that we should divide
a= divident
b_ divisor
q_ quotient
r._remainder
example 237 and 81
237=81×2+75
81=75×1+6
75=6×12+3
6=3×2+0
hcf =3
:- till we get remainder has 0 till that we should divide
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