To find the length of
fencing the square
playground we must find
its Perimeter.
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Important Questions for CBSE Class 6 Maths Mensuration Chapter 10
Last Updated: November 16, 2019 by myCBSEguide

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Important Questions for CBSE Class 6 Maths Mensuration Chapter 10. myCBSEguide has just released Chapter Wise Question Answers for class 6 Maths. There chapter wise Practice Questions with complete solutions are available for download in myCBSEguide website and mobile app. These Extra Questions with solution are prepared by our team of expert teachers who are teaching grade in CBSE schools for years. There are around 4-5 set of solved Mathematics Extra questions from each and every chapter. The students will not miss any concept in these Chapter wise question that are specially designed to tackle Exam. We have taken care of every single concept given in CBSE Class 6 Mathematics syllabus and questions are framed as per the latest marking scheme and blue print issued by CBSE for Class 6.
CBSE Class 6 Maths Extra Questions
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CBSE Class 6 Extra Questions for Chapter 10 Mathematics
Ch-10 Mensuration
The side of a square is 12 m. Its perimeter is
144 m
48 m
24 m
36 m
The shape of your class room blackboard is
circle
equilateral triangle
square
rectangle
Which figure encloses more area: a square of side 2 cm ; a rectangle of side 3 cm and 2 cm ;An equilateral triangle of side 4 cm?
None of these
square
equilateral triangle
rectangle
The perimeter of the given figure is

70 cm
None of these
60 cm
100 cm
The area of square is 100 cm2cm2. Its side is
5 cm
10 cm
20 cm
10.5 cm
Match the following:-
ShapesPerimetera. i. 15b. ii. 8c. iii. 24d. iv. 12
Fill in the blanks:-
_____ is a rectangle whose all sides are equal.
The amount of surface enclosed by a figure is called its ____.
For fencing the plot, we need to calculate its _____.
_____ is the sum of all sides.
State True or False:-
For tiling a rectangular Plot, we must calculate its area.
Length and breadth of a Rectangle are 1.5m and 1m. Area is 1.5m2.
The Perimeter of a square is 4 times the length of the side.
To find the length of fencing the square playground we must find its Perimeter.
Find the area of the rectangle whose side are :3 cm and 4 cm
Find the area of the rectangle whose side are :12 m and 21 m
Find the perimeter of each of the following figures given below?



Find the perimeter of the following figure?

Find the perimeter of the following figure given below.

Find the area of the following figure:

The length of rectangle is thrice its breadth and its perimeter is 48cm. Find length and breadth of rectangle.
Ch-10 Mensuration
Answer
(b) 48 m, Explanation: Perimeter of square = 4l4l
here length = 12 m
so, the perimeter = 4 * 12
= 48 m
(d) rectangle, Explanation: Shape of the blackboard in class room is rectangle as the length of the blackboard is more than the breadth it.
(c) equilateral triangle, Explanation: Area of square = l×ll×l , when l = 2 cm , Area = 4 cm2
Area of rectangle = l×bl×b , when l = 3 cm and b = 2 cm , Area =3×23×2 = 6 cm2
Area of an equilateral triangle =(3–√/4)a2(3/4)a2 , when a = 4 cm , Area = 6.93 cm2
so, the area of eqilateral traiangle is more
(d) 100 cm, Explanation: Perimeter means addition of all sides.
So Perimeter of given triangle = 30 + 30 + 40 = 100 cm
(b) 10 cm, Explanation: Area of square = l∗ll∗l here area = 100 cm2cm2 so the lenght is = l=1–√00l=100 length = 10 cm
→→ iii
→→ iv
→→ i
→→ ii
Square
area
Perimeter
Perimeter
True
True
True
True
Area of the rectangle = Length × Breadth = 3 × 4 cm = 12 sq cm
Area of the rectangle = Length × Breadth = 12 m × 21 m = 252 sq m
Perimeter = 3 cm + 3 cm + 3 cm + 3 cm + 3 cm
= 15 cm
Perimeter = 1 cm + 4 cm + 0.5 cm + 2.5 cm + 2.5 cm + 0.5 cm + 4 cm
= 15 cm
Perimeter = 1 cm + 3 cm + 2 cm + 3 cm + 4 cm + 1 cm + 3 cm + 2 cm + 3 cm + 4 cm + 1 cm + 3 cm + 2 cm + 3 cm + 4 cm + 1 cm + 3 cm + 2 cm + 3 cm + 4 cm
= 52 cm
Perimeter
= AB + BC + CD + DE + EF + FG + GH + HI + IJ + JK + KL + LA
= 1 cm + 3 cm + 3 cm + 1 cm + 3 cm + 3 cm + 1 cm + 3 cm + 3 cm + 1 cm + 3 cm + 3 cm
= 28 cm
Perimeter
= AB + BC + CD + DA
= 5 cm + 5 cm + 5 cm + 5 cm = 20 cm
Full-filled squares = 2
half-filled squares = 4
Area covered by full squares = 2 ×× 1 sq unit = 2 sq units
Area covered by half squares = 4 ××
Answer:
To find the length of fencing the square playground we must find its Perimeter.