Question

To find the positive value of k for which the equation x^2+kx+y4=0 and x^2-8x+k=0will have real roots
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Answer 1

Answer:

hzjdieifjjdjsjd! !

Answer 2

Answer:

D = b^2 - 4ac

here, D is 0 for equal roots

so,

0= k^2 - 4×1×4

0= k^2 -16

16=k^2

√16=k

4 = k

and the other,

follow the same step by putting other values