To find the resistance of a gold bangle, two diametrically opposite points of the bangle are connected to the two terminals of the left gap of a metre bridge. A resistance of 4Ω is introduced in the right gap. What is the resistance of the bangle if the null point is at 20 cm from the left end?
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Answer:
As we know that fir the condition of the null point we must have
R
2
R
1
=
100−L
L
here we know that
R
2
=4Ω
L = 20 cm
so we have
4
R
1
=
80
20
R
1
=1Ω
now we know that bangle is connected at diametrical ends so we have
2
R
=R
1
R=2Ω
Explanation:
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