Question

To find the value of k,(x-1)is a factor of p(x)=kx^2-x-4

Answer 1

p(x)=kx^2-x-4

Therefore=x-1=x=1

=K(1)^2-1-4

=1k-1-4

=k=-1-4

=k=-5

Answer 2

Thanks for the Question ! .............

Your Answer :-

According to Factor Theorem ,

=> In algebra, the factor theorem is a theorem linking factors and zeros of a polynomial .

So , Basically in Your Question (x-1) is a factor .

so ,

x -1 = 0

x = 1 .

putting value in equation .

=> kx^2 - x - 4  = 0

=> k - 1 -4 = 0

=>  k -5 = 0

=>  k = 5

=> k =5........

#Be Brainly