Question

To find the value of y use the linear equation in one variable: (6y - 7)/(3y + 9) = 1/3​

Answer 1

To find : value of $y$  

Given : $\frac{6y - 7}{3y + 9} = \frac{1}{3}$

Solution :

• To find the value of $y$, we cross multiply denominators of LHS and RHS.

• By performing simple operations like multiplication and division  we find the value of $y$.

        $3(6y - 7 ) = ( 3y + 9) \\18y - 21 = 3y + 9 \\18y - 3y = 21 + 9 \\15y = 30 \\y = 2$  

Hence, value of $y$ is $2$ .

Answer 2

• As per the data given in the question, we have to find the value of the expression.

        Given data:- $\frac{(6y-7)}{3y+9} =\frac{1}{3} .$

        To find:- Value of the expression.

        Solution:-

• Here, we will use the below following steps to find a solution using the transposition method:

• Step 1:- we will Identify the variables and constants in the given simple equation.

• Step 2:-then we Simplify the equation in LHS and RHS.

• Step 3:- Transpose or shift the term on the other side to solve the equation further simplest.

• Step 4:- Simplify the equation using arithmetic operation as required that is mentioned in rule 1 or rule 2 of linear equations.

• Step 5:- Then the result will be the solution for the given linear equation. By using the transposition method. we get,

         $\begin{array}{l}3(6 y-7)=(3 y+9) \\18 y-21=3 y+9 \\18 y-3 y=21+9 \\15 y=30 \\y=2\end{array}$

      Hence we will get the value $y=2.$