Question

To get a resultant displacement of 10cm, two displacement vectors, one of magnitude 6cm and another of 8cm, should be combined:

Answer 1

Given first displacement d2=6 m

and 2nd displacement d2=8 m.

(a) when their resultant R=14 m ,let the angle between the displacement be α

So

R2=d21+d22+2d1d2cosα

⇒142=62+82+2⋅6⋅8⋅cosα

⇒cosα=142−62−822⋅6⋅8=9696=1

So α=0∘

(b) when their resultant R=2 m ,let the angle between the displacement be β

So

R2=d21+d22+2d1d2cosβ

⇒22=62+82+2⋅6⋅8⋅cosβ

⇒cosβ=22−62−822⋅6⋅8=−9696=−1

So β=180∘

(c) when their resultant R=10 m ,let the angle between the displacement be γ

So

R2=d21+d22+2d1d2⋅cosγ

⇒102=62+82+2⋅6⋅8⋅cosγ

⇒cosγ=102−62−822⋅6⋅8=096=0

So γ=90∘

Answer 2

Answer:

90 °

Explanation:

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