Question

To get from point A to point B you must avoid walking through a pond. To avoid the pond, you must walk 34 meters south and 41 meters east. To the nearest meter, how many meters would be saved if it were possible to walk through the pond?

Answer 1

Answer:

21.74m

Step-by-step explanation:

34²+41²=C²

1156+1681=2837

√2837=C = 53.26

41+31=75

75-53.26=21.74m

Answer 2

Given:

Distance traveled towards South= 34m

Distance traveled towards East= 41m

To find:

Meters saved if it were possible to walk through the pond

Solution:

Let us find the solution by following the given process-

From the information given above, it is clear that a right-angled triangle is forming between A, B, and the point where we turn from South to East.

Let the point from where we turn towards East be C.

We know that the length of the distance from A to C= 34m

Similarly, the length of the distance from C to B= 41m

As per the Pythagoras theorem,

$height {}^{2} + base {}^{2} = hypotenuse {}^{2}$

Here, AC is the perpendicular height, CB is the base and AB is the hypotenuse.

So,

$34 {}^{2} + 41 {}^{2} = hypotenuse {}^{2}$

Hypotenuse= AB=

$\sqrt{1156 + 1681}$

=53.26m

The distance covered by going South and East=34+41

=75m

The distance covered if it were possible to walk through the pond= AB = 53.26m

So, meters saved= actual distance covered- distance covered through the pond

=75-53.26

=21.74m

Therefore, meters saved if it were possible to walk through the pond is 21 meters, to the nearest.