Question

to get marked as brainliest , find the probability of getting the following, when a dice is thrown:
a) A multiple of 3
b) An even number
c) A prime number
d) A factor of 6
e) A factor of 36

Answer 1

Heya !!!

Here is your answer

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a) multiple of 3 in the dice : 3,6 i.e, 2
P(E) = 2/6 = 1/3

b) An even number : 2,4,6
P(E) = 3/6 = 1/2

c) A prime number : 2,3,5
P(E) = 3/6 = 1/2

d) A factor of 6 : 1,2,3,6
P(E) = 4/6 = 2/3

e) A factor of 36 : 1,2,3,4,6
P(E) = 5/6

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I hope this helps you dear friend.

:)

Answer 2

when a dice is thrown ..
we can get

1. 2. 3. 4. 5. 6.

and according to you question

e.i.,


a) multiple of 3 (less than 6) are- 3 and 6 which is two numbers ....

$p = \frac{2}{6} = \frac{1}{3}$


b)an even number are - 2, 4 and 6
which is 3


$p = \frac{3}{6} = \frac{1}{3}$


c) a prime number - 2,3 and 5
which is 3

$p = \frac{3}{6} = \frac{1}{3}$
d)factor of 6. e.i.,- 1,2,3 and 6
which 4

$p = \frac{4}{6} = \frac{2}{3}$

e) factor of 36 - 1, 2,3,4 and 6

which is 5


$p = \frac{5}{6}$




hope its helpful Friend


;-)