Question

to get x3.....................

Answer 1

Let the number be x.

2xxx - yyy + 3y - 3 + x = xxx + yyy + 2y + 1

2xxx - yyy + 3y - 3 - xxx - yyy - 2y - 1

2xxx-xxx - yyy-yyy + 3y-2y - 3-1 = x

xxx - 0 + y - 4 = x

xxx + y - 4 = x

Therefore, xxx + y - 4 should be added...