Question

to identify the gas evolved by treating dilute . sulphuric acid with zinc
Plse tell me right answer ....
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Answer 1

$\large \underline{ \pmb { \frak{Required \: Answer : - }}}$

• Hydrogen gas

$\large \underline{ \pmb { \frak{Explanation : - }}}$

• When dilute Sulphuric acid is treated with zinc. Hydrogen gas is released along with the formation of Zinc Sulphate.

• Always remember that whenever a metal is treated with an acid, hydrogen gas is released along with the formation of a salt of that metal.

The general reaction can be stated as follows :-

$\implies$ $\large \underline{ \boxed{ \sf metal + acid \longrightarrow salt + H_{2}(g) }} \bigstar$

• According to the question asked by you, Zinc Sulphate will be the salt in this reaction.
• The reaction is outlined below :-

$\implies$ $\underline {\boxed{ \sf Zn + H_{2}SO_{4} \longrightarrow ZnSO_{4} + H_{2}}} \bigstar$

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Hope it's Helpful :D

Answer 2

Explanation:

Answer. Hydrogen

Solution. Hydrogen gas is evolved when a piece of zinc metals is placed in dilute sulphuric acid (H2SO4) . The chemical reaction is. Zn+H2SO4→ZnSO4+H2↑