Question

to If the mass of 100 cm3 of iron is 785 g, then the
density of iron in SI unit is​

Answer 1

Answer:

7850 kg/m³

Explanation:

m = 785 g =  $\frac{785}{1000}$  kg   ⇒ m = 0.785 kg

v = 100 cm³ = 100 × ($10^{-2}$)³ m³     ⇒ v = $10^{-4}$ m³

 also, density = $\frac{mass}{volume}$

                       = $\frac{0.785}{10^{-4} }$   =  0.785 × $10^{4\\}$

  ∴ density = 7850 kg/m³