Math, asked by vishwaschoudhar, 1 year ago

To keep the product of 2 numbers same, If one is increased by 40% then by what % will the  2^{nd} be decreased


AndyKate: Repeat the full question clearly
vishwaschoudhar: the question states that there are tow numbers if we multiply the both we get some answes so now we when the first number is increased by 40% so by how many % shall the second number be decreased in order to keep the product same
AndyKate: ok
vishwaschoudhar: if u have the answer only then ask
vishwaschoudhar: bout the Q
vishwaschoudhar: or do you know how to solve it
vishwaschoudhar: just lik SHERON
AndyKate: wait let me just find out the process from book
vishwaschoudhar: thanks

Answers

Answered by TPS
3
Let the two numbers be X and Y.
product = XY
let X is decreased by 40%
40% of X = (40/100)× X = 40X/100 = 0.4X
by reducing X by 40%, it becomes x
x = X - 0.4X = 0.6X

Let Y becomes y after increasing.
xy = XY
⇒ 0.6X × y = XY
⇒ y = XY/0.6X
⇒ y = Y/0.6 = 10Y/6 
⇒y = = 5Y/3

% increase =  \frac{ \frac{5Y}{3}  -Y}{Y} *100= \frac{ \frac{5Y-3Y}{3} }{Y} *100= \frac{2Y}{3Y} *100= \frac{100*2}{3} =66.7%
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