Question

To lift an.automobile of 1600 kg, a hydraulic pump with a larger piston 800 cm^2 in area is employed. If the area of the smaller piston is 10 cm^2, the force that must be applied on it is
1. 20 N
2. 20 kgf
3. 200 kgf
4. 2000 N

Answer 1

answer : option (2) 20kgf

explanation : mass of automobile , M = 1600kg

so, weight of automobile , F1 = Mg = 1600 kgf

area of cross sectional of larger piston , A1 = 800 cm²

let the force that must be applied on smaller piston is F2.

area of cross sectional of smaller piston, A2 = 10cm²

from Pascal's principle, P1 = P2

⇒ F1/A1 = F2/A2

⇒1600kgf/800cm² = F2/10cm²

⇒2 = F2/10

⇒F2 = 20kgf

hence, option (2) is correct choice.

Answer 2

$\huge\bold\purple{Answer:-}$

20 kgf