To maintain a rotor at a uniform angular speed of 200 rad s-1, an engine needs to transmit a torque of 180 N m. What is the power required by the engine ? (Note: uniform angular velocity in the absence of friction implies zero torque. In practice, applied torque is needed to counter frictional torque). Assume that the
engine is 100% efficient
Answers
Answered by
2
Answer:
Explanation:
Given,
The angular speed of the rotor, ω = 200 rad/s
Torque, T = 180 Nm
Therefore, power of the rotor (P) :
P = T ω
= 200 × 180
= 36.0 kW
Therefore, the engine requires 36.0 kW of power.
Answered by
1
Answer:
Please find below a bit of a new one. To the extent of the most of the most of the most of the
Similar questions