Question

To maintain a rotor at uniform speed of 200 rad/sec ,an engine needs to transmit a torque of 180 Nm .what is the power?

Answer 1

$\huge\underline\blue{\sf Answer:}$

$\large\red{\boxed{\sf Power(P)=36\:kW}}$

$\huge\underline\blue{\sf Solution:}$

$\large\underline\pink{\sf Given: }$

• Speed ($\omega$)=200rad/s

• Torque ($\sf{\tau}$)=180Nm

$\large\underline\pink{\sf To\:Find: }$

• Power (P) = ?

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Power of rotor is ,

$\large{♡}$$\large{\boxed{\sf Power(P)=\tau ×\omega}}$

On Putting value :

$\large\implies{\sf 180×200 }$

$\large\implies{\sf 36×{10}^{3} }$

$\large\implies{\sf 36\:kW}$

$\huge\red{♡}$$\large\red{\boxed{\sf Power(P)=36\:kW}}$