Question

To make a saturated solution ,36 g of sodium chloride is dissolved in100g of water at 293k. Find its concentration of solution.

Answer 1

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(a) To make a saturated solution, 36g of sodium chloride is dissolved in 100g of water at 293 K. Find its concentration at this temperature.

(b) What is the effect of temperature on the solubility of a solid in liquid?

(c) Why is it possible to distinguish the particles of solute from those of solvent in a suspension?

Asked by Topperlearning User | 7th May, 2014, 01:58: PM

Expert Answer:

(a) Mass of solute = 36 g

Mass of solvent = 100g

Mass of solution = 100 + 36

= 136g

Concentration of solution = (Mass of solute / Mass of solution ) x100

= (36/136) x 100

= 26.47%

(b) If temperature increases, solubility increases and if temperature decreases, solubility decreases.

(c) Because particle size is bigger in suspensions hence it is easier to distinguish the particles of solute.

Answer 2

Answer:

$\huge\mathfrak\orange{Answer:-}$

At temperature 293K -

Mass of solute substance (Sodium Chloride) = 36g

Mass of solvent (Water) = 100g

Mass of solution = Mass of solute substance + Mass of solvent

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 36g + 100g = 136g

Concentration (Strength) of solution = (Mass of Solute/Mass of Solution) × 100

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = (36/136) × 100

Answer : 26.47%