Question

To make a saturated solution, 36 g of sodium chloride is dissolved in 100 g of water at 293 K. The solution is warmed to 300k and more 14 g of sodium chloride is added. At which temperature is the solution more concentrated? Pls answer fast!

Answer 1

Explanation:

1.a)mass of solute = 36 g

2.mass of solvent = 100 g

3.mass of solution = 100+36=136g

4.Concentration of solution (mass of solute/mass of solution)×100

5.=(36/136)×100

6.26.47%

7.b)if temperature increases, solubility increases and if temperature decreases, solubility decreases.

Answer 2

Answer:

$Mass of sodium \: chloride (solution) = 36 g \: Mass \: of \: water (solvent) = 100 g \: Total \: mass of solution = 100 + 36 = 136 g \: Mass \: percentage \: of solution= mass \: of \: solute \: / \: mass \: of solution X 100 =36/136x100 = 26.47%Massofsodiumchloride(solution)=36gMassofwater(solvent)=100gTotalmassofsolution=100+36=136gMasspercentageofsolution=massofsolute/massofsolutionX100=36/136x100=26.47$