To make a saturated solution 36g of sodium chloride is dessolved in 100g of water at 293k find its concentration at this temperature
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1
Conc.(molarity) = Mol./litre
100g = 100 ml water ...as density = M/V
and it is 1 here
so in 1000 ml 360 g of sodium will be there,
Moles of Na in 360 g = 360/23=15.65 moles
Molarity= 15.65/1000 Mol/ml
= 15.65 Mol/L or Molar
Answered by
0
Solute=36g
solution=(36+100)g =136g
concentration of solution at that temperature= (36/136×100)%=(0.264×100)%=26.4%
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