Question

To make a saturated solution, 72 g of sodium chloride is dissolved in 200 g of water at 25 °C. What is the solubility of solute at the same temperature?
(a) 37 g (b) 37 % (c) 36 g (d) 36 %
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Answer 1

Answer:36%

Explanation

C = mass of solute/mass of solvent * 100(according to prescribed temptature)

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Answer 2

$\\ \bigstar \textcolor{pink}{ \: \underline{ \pmb{\sf Given : - }}}$

$\\ \textcolor{lavender}{\quad \bullet \quad \sf mass \: of \: solute = 72 \: g}$

$\\ \textcolor{lavender}{ \quad\bullet \quad \sf mass \: of \: solvent = 200 \: g}$

$\\ \bigstar \textcolor{pink}{ \: \underline{ \pmb{\sf To \: Find : - }}}$

$\\ \textcolor{lavender}{ \quad\bullet \quad \sf solubility \: of \: solute}$

$\\ \bigstar \textcolor{pink}{ \: \underline{ \pmb{\sf Formula : - }}}$

$\\ \quad \bullet \quad \textcolor{lavender}{\dag\boxed{ \frak{solubility = \frac{mass \: of \: solute}{mass \: of \: solvent} \times 100}} }$

$\\ \bigstar \textcolor{pink}{ \: \underline{ \pmb{\sf Solution : - }}}$

$\\ \textcolor{lavender}{ \quad \longrightarrow \quad \sf solubility = \dfrac{72}{200} \times 100 }$

$\\ \quad \textcolor{lavender}{ \longrightarrow \quad \sf solubility = \dfrac{72}{2} }$

$\\ \quad \textcolor{lavender}{ \longrightarrow \quad \boxed{\frak{ solubility = 36\% }}}$

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