Question

to maths Aryabhatta only.


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my question photo is not clear means ask question number, I will type it in comment box. For Intelligent.

Answer 1

(1). Answer: Option (B).

     Explanation:

Given Question is ($( \frac{-2}{3})^-4$

= $\frac{1}{( \frac{2}{3})^4 }$

= $\frac{1}{ \frac{2^4}{3^4} }$

= $\frac{3^4}{2^4}$

= $\frac{81}{16}$



(2) Answer - Option (A).

Explanation:

Given Decimal form of 0.04 * 10^-3

= $0.04 * \frac{1}{10^3}$

= $\frac{0.04}{10^3}$

= $\frac{0.04}{1000}$

= 0.00004.



(3) Answer: Option (C)

Explanation:

Given Standard form of 526.007

= 0.526007 * 10^6.

= 526.007.



(4).Answer:Option (B)

Explanation:

Given $4^{x} = \frac{1}{32}$

         $(2^2)^x = 32^-1$

         $2^{2x} = 32^{-1}$

         $2^{2x} = 2^{5^{(-1)} }$

         $2^{2x} = 2^{-5}$

         2x = -5

          x = $\frac{-5}{2}$


           

(5) This Question is not clearly visible.

     I think (3/5)^3 - 2x = (5/3)^3

                (5/3)^-1 (3 - 2x) = (5/3)^3

                3 - 2x = -3

                    -2x = -6

                     x = 3.



(6) Option: A

Explanation:

Given Equation is $(243)^{ \frac{-1}{5} }$

                             = $\frac{1}{(243)^{ \frac{1}{5} } }$

                             = $\frac{1}{(3^5)^ \frac{1}{5} }$

                             = $\frac{1}{(3)^5* \frac{1}{5} }$

                             = $\frac{1}{3}$





(7) Given Equation is (a/b)^1/2 = (b/a)^1-2x

                                   (a/b)^1/2 = (a/b)^-(1 - 2x)

                                   1 - 2x = -1/2

                                   -2x = -3/2

                                     x = 3/4



(8) It's not visible.


(9) Option (C).

Explanation:

Given Equation is 3^3 - 9 * 3^0 - 1/3^-4

                             = 3^3 - 9 * 1 - 3^4

                             = 3^3 - 1 * 9 - 3^4

                             = 3^3 - 9 - 3^4

                             = 27 - 9 - 81

                             = -63.



(10) Answer: Option (A).

Explanation:


Given Equation is $3 * 10^{2} + \frac{1}{ 10^{2} } + \frac{1}{ 10^{3} }$

                            = $3 * 10^2 + \frac{1}{1000}$

                            = $300 + \frac{11}{1000}$

                            = $\frac{(300 * 1000) + 11}{1000}$

                            = $\frac{300011}{1000}$

                            = 300.011.


Hope this helps!