To measure moderately low pressures oil with a density of 8.5 × 102 kg/m3 is used in
place of mercury in a barometer. A change in the height of the oil column of 1.0 mm
indicates a change in pressure of about:
A. 1.2 × 10−7 Pa B. 1.2 × 10−5 Pa C. 1.2 Pa D. 8.3 Pa
Answers
Answered by
6
To measure moderately low pressures oil with a density of 8.5 × 10² kg/m³ is used in place of mercury in a barometer. A change in the height of the oil column of 1.0 mm.
We have to find the change in pressure.
using formula, P = ρgh
- ρ is density of liquid oil.
- g is acceleration due to gravity
- h is height of oil column.
here,
- ρ = 8.5 × 10² kg/m³
- g = 9.8 m/s²
- h = 1mm = 10¯³ m
so, pressure = 8.5 × 10² × 9.8 × 10¯³
= 8.33 Pa [ nearest value of 8.3 Pa , option (D) ]
Therefore the correct option is (D) 8.3 Pa.
Similar questions