Question

to move charge q from point a to b request -30j.finde the voltage drop Vab (a) q=2c (b) q= -6c

Answer 1

Answer: (a) -15 V, (b) +5 V

Explanation:

The work done in moving a charge q from a point a to another point b is given by the relation:

$W = q V_{ab}$

where, $V_{ab}$  is the potential difference between the two points.

So we have , $V_{ab} = \frac{W}{q}$

Solution for part (a):

W = -30 J ;  q = 2 C

so,   $V_{ab} = \frac{-30 J}{2 C} = -15 V$

Solution for part (a):

W = -30 J ;  q = -6 C

So,   $V_{ab} = \frac{-30 J}{-6 C} = +5 V$