to move the oil drum, the resultant of the three forces shown must have a magnitude of 500 N determine the magnitude and direction of the smallest force F would cause the drum to move
Answers
Answered by
0
hvvvvvcyvgyvyvyvyvyvuvvuvib
Answered by
2
Answer:
Solution: Let us first add up the the two forces
already defined,i.e. 250N( (250\mathbfj
)(250\mathbfj) ) and 300N( (300cos(25)\mathbfi−300sin(25)\mathbfj)(300cos(25)\mathbfi−300sin(25)\mathbfj) ), Resultant of two forces, R=250\mathbfj+(300cos(25)\mathbfi−300sin(25)\mathbfj)R=250\mathbfj+(300cos(25)\mathbfi−300sin(25)\mathbfj) =271.8923\mathbfi−123.2145\mathbfj=298.5084<24.3788o=271.8923\mathbfi−123.2145\mathbfj=298.5084<24.3788o F...
if my answer is correct so plz branlist me
Similar questions