Question

To neutralize 20 ml of NaOH, the volume of 1 M HNO3 is :-​

Answer 1

Answer: 40ml

Explanation :

n-factor of NaOH = 1

n-factor of HCL= 1

as we know N1 V1 = N2 V2

(0.1×1)(.02)=(.05×1)×V2

V2 = 0.04L

V2 = 40ml