Question

to neutralize 200 ml of ba(oh)2 solution, we have to add 100ml of 0.1M h2so4 solution. what is the normality of ba(oh2)

Answer 1

Answer:

Normality of barium hydroxide solution =0.1 N

Explanation:

Considering:-

Normality=Molarity\times {n-factor}Normality=Molarity×n−factor

So, Given that:-

Molarity of H_2SO_4H

2

SO

4

= 0.1 M

n-factor of H_2SO_4H

2

SO

4

= 2 (As seen from the from the formula that it has 2 dissociable H)

So,

Normality of H_2SO_4H

2

SO

4

= 0.1*2 N = 0.2 N

Considering:-

At equivalence point

Gram equivalents of H_2SO_4H

2

SO

4

= Gram equivalents of Ba(OH)_2Ba(OH)

2

So,

Normality_{H_2SO_4}\times Volume_{H_2SO_4}=Normality_{Ba(OH)_2}\times Volume_{Ba(OH)_2}Normality

H

2

SO

4

×Volume

H

2

SO

4

=Normality

Ba(OH)

2

×Volume

Ba(OH)

2

Given that:

Normality_{H_2SO_4}=0.2\ NNormality

H

2

SO

4

=0.2 N

Volume_{H_2SO_4}=100\ ccVolume

H

2

SO

4

=100 cc

Volume_{Ba(OH)_2}=200\ ccVolume

Ba(OH)

2

=200 cc

So,

0.2\times 100=Normality_{Ba(OH)_2}\times 2000.2×100=Normality

Ba(OH)

2

×200

Normality_{Ba(OH)_2}=0.1\ NNormality

Ba(OH)

2

=0.1 N