Question

to neutralize completely 20 ML of 0.1M phosphoric acid solution ,The volume of 1M KOH SOLUTION RQUIRED IS

Answer 1

Answer:

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Explanation:

The neutralization reaction is H

3

PO

3

+2KOH→K

2

HPO

3

+2H

2

O.

Phosphorus acid is diprotic acid as it has two ionizable hydrogens.

Thus, 1 mole of phosphorous acid will neutralize 2 moles of KOH.

The number of moles of phosphorus acid present in 20 mL of 0.1 M aqueous solution is 0.1×20×

1000

1

=0.002 mol.

They will neutralize 2×0.002 mol =0.004 moles of KOH.

The molarity of KOH solution is 0.1 M.

The volume of KOH solution required will be

0.1

0.004

=0.04L=40 ml.