Physics, asked by krishnavarsith111, 1 month ago

to observe diffraction, the size of an obstacle may become smaller (or) greater than the wavelength true /false​

Answers

Answered by KillerXoo7
2

Answer:

FALSE

Explanation:

The amount of diffraction (the sharpness of the bending) increases with increasing wavelength and decreases with decreasing wavelength. In fact, when the wavelength of the wave is smaller than the obstacle or opening, no noticeable diffraction occurs

Answered by Dhaarini22
1

Answer:

hy

Explanation:

Diffraction is basically bending of waves.

The bending occurs due to obstacles.

It occurs only when the the wavelength is comaparable to the size of aperture.

As the wavelength increases, the diffraction effect will also increase.

Thus for greater diffraction it is important that the size of obstacle is directly proportional to the wavelength of source.

Suppose a is diffraction and λ is the wavelength a ∝ λ

Hence for diffraction, size of obstacle should be in order of wavelength

so it Should be of the same order as wavelength.

true

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