Question

To obtain 5 image from two plane mirror, then angle between them is........
a) 120°
b) 900
c) 60°
d) 45°
​

Answer 1

60°

Answer:

The number of images formed n=(360/A)-1, if (360/A) is even integer.If (360/A) is odd integer, the number of images formed n=(360/A)-1 when the object is kept symmetrically, and n=(360/A) when object is kept asymmetrically.

The number of images formed n=(360/A)-1, if (360/A) is even integer.If (360/A) is odd integer, the number of images formed n=(360/A)-1 when the object is kept symmetrically, and n=(360/A) when object is kept asymmetrically.If (360/A) is a fraction, the number of images formed is equal to its integral part.

The number of images formed n=(360/A)-1, if (360/A) is even integer.If (360/A) is odd integer, the number of images formed n=(360/A)-1 when the object is kept symmetrically, and n=(360/A) when object is kept asymmetrically.If (360/A) is a fraction, the number of images formed is equal to its integral part.As the angle gets smaller (down to 0 degrees when the mirrors are facing each other and parallel) the smaller the angle the greater the number of images.

The number of images formed n=(360/A)-1, if (360/A) is even integer.If (360/A) is odd integer, the number of images formed n=(360/A)-1 when the object is kept symmetrically, and n=(360/A) when object is kept asymmetrically.If (360/A) is a fraction, the number of images formed is equal to its integral part.As the angle gets smaller (down to 0 degrees when the mirrors are facing each other and parallel) the smaller the angle the greater the number of images.Here, the angle A between the mirrors is 40 degrees.

The number of images formed n=(360/A)-1, if (360/A) is even integer.If (360/A) is odd integer, the number of images formed n=(360/A)-1 when the object is kept symmetrically, and n=(360/A) when object is kept asymmetrically.If (360/A) is a fraction, the number of images formed is equal to its integral part.As the angle gets smaller (down to 0 degrees when the mirrors are facing each other and parallel) the smaller the angle the greater the number of images.Here, the angle A between the mirrors is 40 degrees.Case (a): The object is symmetrically placed.

The number of images formed n=(360/A)-1, if (360/A) is even integer.If (360/A) is odd integer, the number of images formed n=(360/A)-1 when the object is kept symmetrically, and n=(360/A) when object is kept asymmetrically.If (360/A) is a fraction, the number of images formed is equal to its integral part.As the angle gets smaller (down to 0 degrees when the mirrors are facing each other and parallel) the smaller the angle the greater the number of images.Here, the angle A between the mirrors is 40 degrees.Case (a): The object is symmetrically placed. The number of images formed = (360/40)-1, we get 8 images.

The number of images formed n=(360/A)-1, if (360/A) is even integer.If (360/A) is odd integer, the number of images formed n=(360/A)-1 when the object is kept symmetrically, and n=(360/A) when object is kept asymmetrically.If (360/A) is a fraction, the number of images formed is equal to its integral part.As the angle gets smaller (down to 0 degrees when the mirrors are facing each other and parallel) the smaller the angle the greater the number of images.Here, the angle A between the mirrors is 40 degrees.Case (a): The object is symmetrically placed. The number of images formed = (360/40)-1, we get 8 images.Case (b): The object is asymmetrically placed.

The number of images formed n=(360/A)-1, if (360/A) is even integer.If (360/A) is odd integer, the number of images formed n=(360/A)-1 when the object is kept symmetrically, and n=(360/A) when object is kept asymmetrically.If (360/A) is a fraction, the number of images formed is equal to its integral part.As the angle gets smaller (down to 0 degrees when the mirrors are facing each other and parallel) the smaller the angle the greater the number of images.Here, the angle A between the mirrors is 40 degrees.Case (a): The object is symmetrically placed. The number of images formed = (360/40)-1, we get 8 images.Case (b): The object is asymmetrically placed. The number of images formed = (360/40), we get 9 images.

The number of images formed n=(360/A)-1, if (360/A) is even integer.If (360/A) is odd integer, the number of images formed n=(360/A)-1 when the object is kept symmetrically, and n=(360/A) when object is kept asymmetrically.If (360/A) is a fraction, the number of images formed is equal to its integral part.As the angle gets smaller (down to 0 degrees when the mirrors are facing each other and parallel) the smaller the angle the greater the number of images.Here, the angle A between the mirrors is 40 degrees.Case (a): The object is symmetrically placed. The number of images formed = (360/40)-1, we get 8 images.Case (b): The object is asymmetrically placed. The number of images formed = (360/40), we get 9 images.Hence, the number of images formed are 8 and 9 respectively.

Answer 2

Answer : 60 degree

The number of images formed when two mirrors are placed at an angle theta to each other is given by:

n = ( 360 / theta )-1.

Here, n = 5, so ( 360 / theta ) = n+1 = 6, hence theta = 360/6 = 60 deg.

So the mirrors are placed at an angle of 60 deg with each other.