Question

To obtain an erect image of an object, a concave mirror of focal length 10 cm is used. a) What should be the range of distance of an object placed in front of the mirror? b) Where will be the image of the object if it is placed 25 cm in front of the mirror. Draw the ray diagram for this situation.

Answer 1

Focal length of concave mirror (f) = -10 cm

Height of the object (ho) = 2 cm

Height of the image (hi) = 6 cm

We need to find the object distance

So we know that

Magnification m = hi/ho

hi/ho = 6/2

hi/ho = 3 (erect image)

m = -v/u

3 = -v/u

⇒ v = -3u

Let us now consider Mirror formula

1/v + 1/u = 1/f

1/(-3u) + 1/u = 1/(-10)

⇒ u = -20/3

u = -6.7 cm

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