Question

To obtain maximum mass no2 from a given mass of a mixture of nh3 and o2 the ratio of mass of nh3 and o2 should be nh3 + o2 = no2 + h2o

Answer 1

Answer: The mass ratio of $NH_3:O_2$ is 17 : 56

Explanation:

To obtain maximum amount of nitrogen dioxide from the given equation, we need to balance the equation.

For balancing, we will follow law of conversation of mass.

This law states that total number of individual atoms on the reactant side will be equal to the total number of individual atoms on the product side.

The balanced chemical equation follows:

$4NH_3+7O_2\rightarrow 4NO_2+6H_2O$

Molar mass of ammonia = 17 g/mol

Molar mass of oxygen gas = 32 g/mol

Mass of 4 moles of ammonia = (4 × 17) g

Mass of 7 moles of oxygen gas = (7 × 32) g

Ratio of mass of ammonia and oxygen = $\frac{(4\times 17)}{(7\times 32)}=\frac{17}{56}$

Hence, the mass ratio of $NH_3:O_2$ is 17 : 56

Answer 2

Answer:

17/56

Explanation:

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