Question

to obtain probability of an event related to throw up a pair of dice through an activity
No Spam please write the correct answer​

Answer 1

Answer:

the total outcomes are 36 if a pair of dice is thrown

probability of even number is 1/36

probability of odd number is 1/36

Answer 2

Answer:

Objective:-

To find experimental probability of each outcome of a die when it is thrown a large number of times.

Materials Required:-

Notebook

A fair die

Pen

Prerequisite Knowledge

Basic knowledge of probability and a fair die.

Theory:-

For basic knowledge of probability refer to Activity 33.

A fair die is small cube having dots, 1 to 6 on its faces.

NCERT Class 9 Maths Lab Manual - Find Probability of each Outcome or a Die 1

Procedure

Firstly, divide the whole class in ten groups, say G1, G2, G3, …….., G10 of a suitable size.

Allow all groups to throw a die 100 times and ask them to note down the observations, i.e. the number of times the outcomes 1, 2, 3, 4, 5 or 6 come up.

If 1 appears in all the groups a times. Similarly, count the number of times each of 2, 3, 4, 5 and 6 has appeared. Denote them by b, c, d, e and f, respectively.

Now, find the probability of each outcome (E) by using the formula,

P(E) = \frac { Number\quad of\quad times\quad an\quad outcome\quad occurred }{ Total\quad number\quad of\quad trials }

Demonstration

There are 10 groups and all the groups throw a die 100 times. So, the total number of trials is 1000.

As, 1 has appeared a times.

Hence, experimental probability of 1, P(1) = \frac { a }{ 1000 }

similarly, experimental probability of 2, P(2) = \frac { b }{ 1000 }

experimental probability of 3, P(3) = \frac { c }{ 1000 }

experimental probability of 4, P(4) = \frac { d }{ 1000 }

experimental probability of 5, P(5) = \frac { e }{ 1000 }

and experimental probability of 6, P(6) = \frac { f }{ 1000 }

Thanks have a nice day