Question

To obtain the solution of a quadratic equation (x2 + 4x = 60) by completing the square geometrically | WRITTEN PRACTICAL PLEASE | NO TEXT NEEDED !!!

Answer 1

Answer:

Ans. X= -10 & X =6

Step-by-step explanation:

x^2 +4x-60=0

x^2 +10x -6x -60=0

x(x+10) -6(x+10)=0

And now, it became,

(x+10)=0 & (x-6)=0 then

x=-10 & x=6

Answer 2

Answer:

The values of x= 6, -10.

Step-by-step explanation:

Given $x^{2} +4x=60$

This is in the form of $ax^{2} +bx+c=0$

Find a value that is equal to the square of half of 'b'

$(\frac{b}{2} )^{2} =2^{2}$

Add the term to each side of the equation

$x^{2} +4x+2^{2} =60+2^{2}$

$x^{2} +4x+4=64$

Factor the perfect square into $(x+2)^{2}$.

$(x+2)^{2}$ = 64

Take the square root of both sides of the equation

x+2 = ±√64

x+2 = ± 8

x + 2  = +8,  x+2 = -8

x= 8-2,     x = -8-2

x=6,       x = -10.

Therefore, the values of x= 6, -10.