Question

to point charge q and 10 Q repel each other with a force of 3.6 x 10 raise to minus 5 Newton when there are 0.02 M apart find the charge plz solve the question l will give + 5 point

Answer 1

Given that,

One charge = q

Another charge = 10 q

Distance = 0.02 m

Force $F=3.6\times10^{-5}\ N$

We need to calculate the charge

Using formula of electric force

$F = \dfrac{kq_{1}q_{2}}{r^2}$

$F=\dfrac{1}{4\pi\epsilon_{0}}\dfrac{q_{1}q_{2}}{r^2}$

Where, $q_{1}$ = one charge

$q_{2}$ = another charge

r = distance

F = force

Put the value into the formula

$3.6\times10^{-5}=\dfrac{9\times10^{9}\timesq\times10q}{(0.02)^2}$

$q^2=\dfrac{(0.02)^2\times3.6\times10^{-5}}{9\times10^{9}\times10}$

$q=\sqrt{1.6\times10^{-19}}\ C$

$q=4\times10^{-10}\ C$

Hence, The charge is $4\times10^{-10}\ C$