To prepare 0.02N H2SO4 need to dissolve ________ grams of H2SO4 in 1 Litre of water.
Answers
Answer:
How do you prepare 0.01 N H2SO4?
Preparation of 0.1 N Sulphuric acid (H2SO4) Solution
Take 3.0 mL of concentrated Sulphuric acid (H2so4, sp gr 1.84) into a 1000-ml volumetric flask. Dilute to the mark with water, mix well, and store in a tightly closed glass container.
Explanation:
How do you prepare 0.01 N H2SO4?
Preparation of 0.1 N Sulphuric acid (H2SO4) Solution
Take 3.0 mL of concentrated Sulphuric acid (H2so4, sp gr 1.84) into a 1000-ml volumetric flask. Dilute to the mark with water, mix well, and store in a tightly closed glass container
Answer: To make 0.02 N H₂SO₄, dissolve 0.98 g of H₂SO₄ in 1 L of water.
Let's discuss about normality and the method to solve it.
Explanation:
What is Normality?
The number of gram or mole equivalents of solute contained in one litre of solution is defined as normality.
Formula of Normality
- N = Number of gram equivalents/ V of solution
- N = Solute weight (g)/ V × equivalent weight
- N = M × N-factor
Here, N = Normality, M = Molarity, V = Volume of solution in L.
What exactly is the N-factor?
For acids, N-factor is defined as the number of H⁺ ions replaced by 1 mole of acid in a process.
It should be noted that the N-factor for acid is not equal to its basicity; that is, the number of moles of replaceable H⁺ atoms present in one mole of acid.
For example,
- N-factor of HNO₃ = 1
- N-factor of HCL = 1
- N-factor of H₂CO₃ = 2
- N-factor of H₂SO₄ = 2
Now, let us return to the question and attempt to answer it.
According to the formula,
N = M × N-factor
⇒ M = N / N-factor
We know, N-factor for H₂SO₄ is 2.
So,
M =
M = 0.01 M
This means we need to dissolve 0.01 moles of H₂SO₄ in 1L of water to make a 0.02 N solution.
0.01 M H₂SO₄ = 98 g/0.01 (∵ molecular weight of H₂SO₄ is 98g)
= 0.98 g
To obtain the necessary solution, we dissolve 0.98 g H₂SO₄ in 1 L of water.
Hope, the concept is clear.