Chemistry, asked by maham2k4, 12 hours ago

To prepare 0.02N H2SO4 need to dissolve ________ grams of H2SO4 in 1 Litre of water.​

Answers

Answered by sreeadigseshnj
0

Answer:

How do you prepare 0.01 N H2SO4?

Preparation of 0.1 N Sulphuric acid (H2SO4) Solution

Take 3.0 mL of concentrated Sulphuric acid (H2so4, sp gr 1.84) into a 1000-ml volumetric flask. Dilute to the mark with water, mix well, and store in a tightly closed glass container.

Explanation:

How do you prepare 0.01 N H2SO4?

Preparation of 0.1 N Sulphuric acid (H2SO4) Solution

Take 3.0 mL of concentrated Sulphuric acid (H2so4, sp gr 1.84) into a 1000-ml volumetric flask. Dilute to the mark with water, mix well, and store in a tightly closed glass container

Answered by sameeksha712rawat
2

Answer: To make 0.02 N H₂SO₄, dissolve 0.98 g of H₂SO₄ in 1 L of water.

Let's discuss about normality and the method to solve it.

Explanation:

What is Normality?

The number of gram or mole equivalents of solute contained in one litre of solution is defined as normality.

Formula of Normality

  • N = Number of gram equivalents/ V of solution
  • N = Solute weight (g)/ V × equivalent weight
  • N = M × N-factor

Here, N = Normality, M = Molarity, V = Volume of solution in L.

What exactly is the N-factor?

For acids, N-factor is defined as the number of H⁺ ions replaced by 1 mole of acid in a process.

It should be noted that the N-factor for acid is not equal to its basicity; that is, the number of moles of replaceable H⁺ atoms present in one mole of acid.

For example,

  1. N-factor of HNO₃ = 1
  2. N-factor of HCL = 1
  3. N-factor of H₂CO₃ = 2
  4. N-factor of H₂SO₄ = 2

Now, let us return to the question and attempt to answer it.

According to the formula,

N = M × N-factor

⇒ M = N / N-factor

We know, N-factor for H₂SO₄ is 2.

So,

M = \frac{0.02}{2}

M = 0.01 M

This means we need to dissolve 0.01 moles of H₂SO₄ in 1L of water to make a 0.02 N solution.

0.01 M H₂SO₄ = 98 g/0.01                   (∵ molecular weight of H₂SO₄ is 98g)

                       = 0.98 g

To obtain the necessary solution, we dissolve 0.98 g H₂SO₄ in 1 L of water.

Hope, the concept is clear.

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