Question

To prepare 100 ml of standard O. IM oxalic acid solution
a. 0.61 g of oxalic
acid is dissolved in 100 ml of distilled water.
1.26 of oxalie acid is dissolved in 100 ml of distilled water
e. 12.6 # of oxalie acid is dissolved in 1000 ml of distilled water.
d. 126 8 of oxalic acid is dissolved in 100 ml of distilled water​

Answer 1

Answer :

Molarity = weight*1000/molecular weight*vol

Oxalic acid = COOH.COOH.2H2O

Molecular weight = 126g/mol

n factor=2

weight = ?

Molarity M = 0.1

volume = 100mL

Therefore 0.1 = x * 1000/ 126*100

x = 1.26

In normality

Normality = weight*1000/Equivalent weight*vol

Equivalent weight = 63g/mol

0.1 = x *1000/63*100

x = 0.63g

Explanation :

I hope Help You

Answer 2

Answer:

b. 12.6 g of oxalic acid is dessolved in 1000ml of distilled water