to prepare 10moles of CaCl2, how many grams of HCl is required according to the following reaction? Ca (OH)2 +2HCl ----> Cacl2 +2 H2O
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CaCO3 (s) + 2HCl(aq) → CaCl2(aq) + CO2 O(l) Number of moles of HCl ... with 2 moles of HCl 10 moles of CaCO3 will react with = 2 × 10 = 20 moles of HCl
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