Question

to prepare a saturated solution of common salt ,36 g of sodium chloride are dissolved in 100 g of water at 293 k .find its concentration at this temprature​

Answer 1

Explanation:

Mass of solute = 36 g . Mass of solvent = 100 g. The mass of solution = mass of solute + mass of solvent. = 36+100 = 136. Concentration of solution = mass of solute/ mass of solution × 100. = 36/ 136 × 100 = 26.47%.

Answer 2

Answer:

Mass of solute (sodium chloride) = 36 g

Mass of solvent (water) = 100 g

Mass of solution

= Mass of solute + Mass of solvent

= 36 g + 100 g = 136 g

I have send two answers

To make a saturated solution 36g of sodium chloride dissolve in 100 of water at 293 k find it's concentration at this temperature?

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You have not given the units for 100(?) water. I will assume 100g water

You want a concentration - but you do not give what concentration you want. The one feasible concentration is %m/m

Total mass = 100g + 36g = 136g

concentration %m/m = 36g/136g * 100% = 26.5%m/m

The other concentration you can calculate is molality ( Note: NOT Molarity)

Molality = moles solute / 1.0kjg solvent

Molar mas NaCl = 58.5g/mol

Mol NaCl in 36g/58.5g/mol = 0.615 mol in 100g = 0.1kg water

molality = 0.615mol / 0.1kg = 6.15mol /kg or 6.15m