Question

to prepare a saturated solution of common salt, 36 g of sodium chloride are dissolved in 100 g of water at 293 k. find its concentration at this temperature.


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Answer 1

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• (a) Mass of solute = 36 g.
• Mass of solvent = 100g.
• Mass of solution = 100 + 36.
• = 136g.
• Concentration of solution = (Mass of solute / Mass of solution ) x100.
• = (36/136) x 100.

= 26.47%

• (b) If temperature increases, solubility increases and if temperature decreases, solubility decreases.

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Answer 2

Answer:

Mass of solute = 36g

Mass of solvent = g

Mass of solution =+36

= 136g

concentration of solution =( mass of solution/ mass of solutions)

X

={ 36/136)X

= 26.47%

b) if temperature increases solubility increases and if temperature decrease, solubility decrease

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