Question

to produce 5g hydrogen how much zn with 50% purity is needed in a reaction of mild sulfuric acid and zn​

Answer 1

Zn+H

2

SO

4

→ZnSO

4

+H

2

At STP 224 mL of hydrogen corresponds to

1000×22.4

224

=0.01 moles of hydrogen. They will be produced from the reaction of 0.01 mole of Zn with 0.01 mole of sulphuric acid. Hence, the mass of zinc required is 65.38×0.01=0.65 g.